20210824, 08:30  #485 
"Oliver"
Sep 2017
Porta Westfalica, DE
3·223 Posts 
Next on is a C201. I finished around one and a quarter t55 on it. t60 would take me more than two weeks, so that's heavier than I can lift in a reasonable amount of time, it seems. How high do we want to go? YAFU said t62?
Any help is appreciated! 
20210825, 00:43  #486 
Jun 2012
C83_{16} Posts 
I use 0.31*GNFS difficulty to get the ECM test metric, which is t62 in this case. After this week, I can contribute some t60 cycles if you still need them then.

20210825, 01:58  #487 
"Curtis"
Feb 2005
Riverside, CA
11611_{8} Posts 
My vote (not that you asked for it) is half a t60, then a t60 worth of curves at the t65 level.
C200ish jobs are a whole lot easier and faster than they used to be, so we need less ECM than we used to need. 
20210826, 16:04  #488 
"Oliver"
Sep 2017
Porta Westfalica, DE
1235_{8} Posts 
I'd really appreciate that! On Sunday, I'll likely have finished around 15k18k curves @ B1=260M and 400500 @ B1=850M from another machine.
After doing ECM and assuming no factors, is this a job for team sieving or for some of the NFS@home queues? In the first case, I'd volunteer for hosting a CADO server and to do the LA in the end. I might need some help with the initial setup since I never ran a CADO server with computers all over the world, only locally. But I am going too far into the future right now, I guess. There is still a good chance that we hit something with ECM until then. @VBCurtis: I always appreciate input, especially because I have a lot to learn in this field. I guess "t60 worth of curves" refers to the amount of 260M curves? Last fiddled with by kruoli on 20210826 at 16:04 Reason: Misspelling names is a felony. 
20210826, 16:44  #489 
"Curtis"
Feb 2005
Riverside, CA
3×1,667 Posts 
If you invoke ecm with the v flag, you'll get a table of curve counts for each tvalue in multiples of 5 digits.
So, ecm v 85e7 will tell you how many curves at B1=850M is worth a t60. Doing so shows me 15391 curves, so my advice was 15k curves at 850M after half a normal t60. Edit: C201 is simple for the 16small queue, but if you'd like the experience of hosting a team CADO sieve I'm willing to run clients and advise on management. Should be ~30 coreyears of sieving. You'll need 64GB ram for the postprocessing, or plenty of experience using msieve postprocessing after CADO sieving. Last fiddled with by VBCurtis on 20210826 at 16:46 
20210826, 18:39  #490  
Apr 2020
1F6_{16} Posts 
Depending on the progress of the 4788 poly search, I may be able to run some curves at 850M next week.
Quote:
Msieve postprocessing should fit within 32GB RAM. 

20210826, 20:14  #491 
"Oliver"
Sep 2017
Porta Westfalica, DE
3·223 Posts 
Thanks for the explanation, I now understand what you meant originally.
The RAM reqirements can be met. How much efficiency could be gained by running msieve for LA instead of CADO? 
20210826, 20:44  #492  
"Curtis"
Feb 2005
Riverside, CA
3×1,667 Posts 
Quote:
For the samesized matrix, msieve LA will run in maybe 5060% of the time CADO runs. But, CADO filtering makes smaller matrices for the C207 team sieve, CADO created a matrix around 61M dimensions while msieve on the same data set was 73M dimensions. So, that ate up about half the speed advantage (in very rough terms I think msieve was 11 weeks while CADO would have been 15ish weeks). 

20210826, 22:10  #493  
Jun 2012
3,203 Posts 
Quote:
Quote:


20210827, 07:50  #494 
Aug 2020
79*6581e4;3*2539e3
402_{10} Posts 
While msieve is faster at LA, I often had the problem that cado could build a matrix while msieve couldn't and required more relations.
Depending on the circumstances that might make it faster to use cado for everything, especially if using just a few cores for sieving. 
20210829, 00:54  #495 
Jun 2012
3,203 Posts 
I’ll start ECM with B1=260M shortly. I’ll shoot for 10000 curves, then we can regroup later in the week and see where we are.
Using Code:
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